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Home » Form 3 Physics Exams and Marking Schemes Free

Form 3 Physics Exams and Marking Schemes Free

by Hillary Kangwana
June 26, 2026
in Teachers' Resources
Reading Time: 1 min read
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Name___________________________________________ Index No.____________                            

Candidates signature ____________________                          Date __________________

PHYSICS

PAPER 3

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PRACTICAL 

2 ½ HOURS

 

JOINT EXAMINATION TERM 3

 

INSTRUCTIONS TO CANDIDATES

  • Answer all questions in both sections in the spaces provided in the question paper.
  • Read the whole paper carefully before commencing your work.
  • Marks are given for clear record of the observations actually made, their suitability and accuracy and the use of them.
  • Mathematical tables and electronic calculators may be used.

 

FOR EXAMINER’S USE ONLY

Question Maximum Score Candidate’s Score
1. 20  
2. 20  
 

TOTAL

 

40

 

 

 

This paper consists of 7 printed pages. Learners should check to ensure that all pages are printed as indicated and that no questions are missing.

 

 

 

Question 1

You are provided with the following;

  • Masses; 10g, 20g(2), 50g and 100g
  • A helical spring with a pointer
  • Metre rule or half metre rule

 

Proceeds as follows;

  1. a) Suspend the helical spring vertically, alongside the clamped half metre rule as shown in figure 1 below. Determine the length, L0 of the spring before loading it.

L0=________________________________(cm)                                                      (1mk)

  1. i) Load the spring with a mass of 20g and determine the new reading on the metre rule (L).

 

  1. ii) Record this in the table below.

 

iii) Calculate the extension, e= L-L0 due to the mass of 20g and record the value in the table given below.

 

 

 

 

 

 

 

 

 

 

 

 

  1. Repeat step b(i-iii) for other masses and complete the table.             (8mks)

 

Mass (g) 0 20 30 40 50 60 70 80 90 100
Weight (N) (Force)                    
Reading L (cm)                    
Extension e (cm)                    

 

  1. Plot a graph of Force(N) against extension e (cm).             (5mks)
  • Determine the slope S of the graph.             (3mks)

 

 

 

 

  1. Given that K=Se, determine the value of K where S is the slope of the graph and e is the extension of the spring when loaded with a 50g mass.             (3mks)

 

 

 

 

Question 2

You are provided with the following;

  • A Nichrome wire mounted on a millimeter scale YZ.
  • A carbon resistor R (10Ω)
  • 8 connecting wires
  • Ammeter
  • Voltmeter
  • 2 dry cells
  • Cell holders
  • Switch

 

  1. (a) Set up the circuit as shown below.
  2. Record the voltmeter reading when the switch is open.

E=_____________________________________                                         (1mk)

  1. Close the switch and record the voltmeter and ammeter readings.

Voltmeter reading, V=_______________________________                     (1mk)

Ammeter reading, I=________________________________                      (1mk)

  • Explain why V is less than E.             (2mk)

______________________________________________________________________________________________________________________________________________________________________________________________________

 

  1. Now connect the voltmeter across the carbon resistor R and record voltmeter reading V1 when the switch is on.             (1mk)

V1=

 

 

 

 

 

 

 

  1. Determine R given that; R=             (3mks)

 

 

 

 

 

 

 

 

(b)

  • Measure and record the diameter, d of the resistance wire (YZ) using a micrometer screw gauge.

d= ___________________________________mm

d=___________________________________m                                           (2mks)

  1. ii) Set-up the circuit as shown in figure;

 

  • Determine the current I flowing in the circuit.

I=__________________________________                                                 (1mk)

 

 

  1. Now connect the voltmeter across wire (YZ) and record the p.d, V2 across wire YZ.

V2= ________________________________                                                 (1mk)

 

  1. Determine the resistance R of the wire YZ.             (3mks)

 

 

 

 

 

 

 

  1. Determine k, the resistance per metre of wire YZ. (2mks)

 

 

 

 

 

 

 

 

 

  • Determine Q given that Q=(where d is in metres)                    (2mks)

________________________________________________________________________

JOINT EXAMINATION

FORM 3PP3 PHYSICS

TERM 3 MARKING SCHEME

 

  1. a) L0 – ½mk answer to 1d.p

½mk correct unit (cm)

 

  1. ii) (8mks)
Mass (g) 0 20 30 40 50 60 70 80 90 100
Weight (force) N                    
Reading, L cm                    
Extension, e(cm)   1.0 2.6 4.8 6.3 8.1 10.2 12.3 14.2 16.4

 

2mks@ Row (force) – correct evaluation and substitution

F = mg

L to 1 d.p

e correct (L-L0) to 1 d.p

 

  1. v) Graph of Force(N) vs extension, e (cm). (5mks)

Correct labelling of axis – 1mk

Scale – simple and uniform – 1mk

Plotting (2mks) (7-10 points) – 2mks

(5-6 points) – 1mk

(0-4 points) – 0 mk

Line – straight line passing through the origin – 1mk

 

  1. vi) Slope, s== 0.8N/cm                         (3mk)

Clear points from the graph – 1mk

Correct evaluation – 1mk

Answer – ½mk

Correct unit – ½mk

 

vii) Correct substitution of k=se – 1mk

Correct evaluation – 1mk

Answer – ½mk

Correct unit – ½mk

  1. a)
  2. E = 3.0- ½mk

Correct unit – ½mk

  1. V = 2.5v1 1 d.p (1mk) and correct unit

I = 0.20A 0.02 2 d.p (1mk) and correct unit

  • V is less than E due to the lost voltage; voltage against the internal resistance of the cell. (2mk)
  1. V1 = 1.4V1 Correct reading to 1 d.p – ½mk

Correct unit – ½mk

  1. R=1

Correct substitution – ½mk

Correct evaluation – ½mk

Answer in 4s.f – ½mk

Correct unit – ½mk

 

b          (i)        d=0.36mm

d= in metres – correct conversion to 5 d.p  (1mk)

(iii)      I = 0.10A     Correct reading – ½mk

Correct unit – ½mk

iv)V2 = 1.9v  0.1      Correct reading – ½mk

Correct unit – ½mk

  1. v) R= Correct substitution – 1mk

Correct evaluation – 1mk

Answer in 4s.f – ½mk

Correct unit – ½mk

  1. K=Correct evaluation – 1mk

Answer – ½mk 4s.f

Correct unit – ½mk (Ωm-1)

  • Q= Correct evaluation – 1mk

Answer in 4s.f – ½mk

Correct unit – ½mk  (Ωm)

 

 

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