CHAPTER NINE
PHOTOELECTRIC EFFECT
Photoelectric effect was discovered by Heinrich Hertz in 1887. Photoelectric effect is a phenomenon in which electrons are emitted from the surface of a substance when certain electromagnetic radiation falls on it.
Metal surfaces require ultra-violet radiation while caesium oxide needs a visible light i.e. optical spectrum (sunlight).
DEMONSTRATING PHOTOELECTRIC EFFECT
Using Neutral Plates
Procedure
- Set up the apparatus as shown in figure 9
- Direct UV-radiation towards plate A. Observe what happens to the galvanometer.
- Place the glass barrier in between the source and plate A and again observe what happens.
Observation
When ultraviolet radiation is allowed to fall on metal plate A, the galvanometer shows deflection.
When the barrier is introduced so that the radiation is cut off, the galvanometer shows no deflection .
Explanation
When ultraviolet radiation energy falls on a metal surface, some electrons absorb this energy and are dislodged from the surface.
The deflection of the galvanometer indicates that electrons are emitted at plate A and attracted by the plate B, causing a current to flow.
The glass plate, however, cuts off the ultraviolet radiation.
(b) Using Charged Electroscope
Procedure
- Direct ultraviolet radiation from a mercury vapour lamp onto the zinc plate and observe the divergence of the leaf when the electroscope is positively charged, see figure
Observation
For the positively charged electroscope, the leaf divergence remains the same. However, for the negatively charged electroscope, the leaf divergence decreases.
Explanation
When the zinc plate is irradiated with ultraviolet radiation, electrons are emitted from its surface.
The photoelectrons emitted from the positively charged zinc plate do not escape due to attraction by the positive charge on the plate and the leaf divergence therefore remains the same.
The photoelectrons emitted from the negatively charged zinc plate are repelled and the electroscope becomes discharged as a result of which the leaf divergence decreases.
If a sheet of ordinary glass (which absorbs ultraviolet radiation) is introduced between the negatively charged zinc plate and the ultraviolet source, the leaf divergence remains same.
Light Energy and Quantum Theory
Max Planck in 1901 came up with the idea that light energy is propagated as small packets of energy.
Each packet is called a quantum of energy (plural: quanta).
In light, these discrete amounts of energy are called photons.
According to Planck, the energy E possessed by one photon is given by; E = hf, where, h is Planck’s constant equal to 6.63 x 10-34 J s and f the frequency of the radiation.
c=fλ
Hence
Thus where c is the velocity of the radiation in vacuum and λ is the wavelength.
Since c and h are constant, a radiation of longer wavelength has lower energy
Terms used in photoelectric effect
Work function W₀
A minimum amount of work is needed to remove an electron from its energy level so as to overcome the forces binding it to the surface.
This work is known as the work function with units of electron volts (eV). One electron volt is the work done when one electron is transferred between points with a potential difference of one volt; that is,
1 eV = 1 electron × 1 volt
1 eV = 1.6 × 10-19 × 1 volt
- eV = 1.6× 10-19 Joules (J)
Threshold frequency f₀
This is the minimum frequency of the radiation that will cause a photoelectric effect on a certain surface. The higher the work function, the higher the threshold frequency.
Threshold Wavelength λ₀
This is the maximum the maximum wavelength beyond which no photoelectric emission will occur.
Work function W₀=hf₀
For any radiation of frequency f less than f₀, hf will be lower than W0 and emission will not occur.
When the frequency of the radiation is fo‘ hf₀ = W₀ (the work function), and emission occurs.
When the frequency of the radiation f > f₀, hf > W₀ and the excess energy in this case appears as the kinetic energy of the emitted electron.
Factors affecting the photoelectric effect
- Intensity of the incident radiation– the rate of emission of photoelectrons is directly proportional to the intensity of incident radiation.
- Type of the metal/Work function of the surface– photoelectrons are emitted at different velocities with the maximum being processed by the ones at the surface.
- Energy of the incident radiation– the cut-off potential for each surface is directly proportional to the frequency of the incident radiation.
The graph of the frequency of the stopping potential against frequency of the radiation is a straight line as shown below
The graph is a straight line. From Einstein’s photoelectric equation;
Work done by stopping potential is given by ev.
By work energy theorem,
Substituting in Einstein’s photoelectric equation;
hf= hfo + eVs
Therefore, e Vs = hf – hf₀
But hf₀ is equal to work function W₀. Hence, the graph of Vs against f is straight line cutting the f-axis at f₀.
The slope of the graph is and the Vs. intercept is
Both Planck’s constant h and the work function W₀ can therefore be calculated from the graph.
Einstein’s photoelectric equation
When a photon strikes an electron, all its energy is absorbed by the electron.
Some of the absorbed energy is used to dislodge the electron from the metal surface while the rest appears as the kinetic energy of the emitted electron.
The energy transformation during photoelectric emission is thus summed as follows;
Examples
- The cut-off wavelength for a certain material is 3.310 × 10-7 What is the cut-off frequency for the material?
Solution
Speed of light ‘c’ = 3.0 × 108 m/s. Since f = c / λ, then f = 3.0 × 108 / 3.310 × 10-7 = 9.06 × 1014 Hz.
- The work function of tungsten is 4.52 e V. Find the cut-off potential for photoelectrons when a tungsten surface is illuminated with radiation of wavelength 50 × 10-7 m. (Planck’s constant, h = 6.62 × 10-34 Js).
Solution
Frequency ‘f’ = c / λ = 3.0 × 108 / 2.50 × 10-7.
Energy of photon = h f = 6.62 × 10-34 × (3.0 × 108 / 2.50 × 10-7) × (1 / 1.6 × 10-19) = 4.97 eV.
Hence h fco = 4.52 e V. e V co = 4.97 e V – 4.52 e V = 0.45 e V = 7.2 × 10-20 J V co = 7.2 × 10-20 / 1.6 × 10-19 = 0.45 e V.
- The threshold frequency for lithium is 5.5 × 1014 Calculate the work function for lithium. (Take ‘h’ = 6.626 × 10-34 Js)
Solution
Threshold frequency, f o = 5.5 × 1014 Hz, ‘h’ = 6.626 × 10-34 Js
Φ = h f = 5.5 × 1014× 6.626 × 10-34 = 36.4 × 10-20 4. Sodium has a work function of 2.0 e V. Calculate
- The maximum energy and velocity of the emitted electrons when sodium is Illuminated by a radiation of wavelength 150 nm.
- Determine the least frequency of radiation by which electrons are emitted. (Take ‘h’ = 6.626 × 10-34 Js, e = 1.6 × 10-19, c = 3.0 × 108 m/s and mass of electron = 9.1 × 10-31 kg).
Solution
- a) The energy of incident photon is given by h f = c / λ
= (6.626 × 10-34 × 3.0 × 108) / 1.50 × 10-9 = 1.325 × 10-18 J
K.E max = h f – Φ = (1.325 × 10-18) – (2 × 1.6 × 10-19) = 1.0 × 10 -18 J (max. K.E of the emitted electrons)
But K.E max = ½ m v2max. Therefore;
1.0 × 10 -18 = ½ × 9.1 × 10-31 × V2max
V2max = (1.0 × 10 -18 / 9.1 × 10-31)1/2 = 1.5 × 106 m/s (max. velocity of emitted electrons).
- b) Φ = h f co and f o = Φ / λ, Φ = 2 × 1.6 × 10-19 fo = (2 × 1.6 × 10-19) / (6.626 × 10-34) = 4.8 × 1014 Hz ( threshold frequency of
the emitted electrons)
Applications of photoelectric effect
Photo-emissive cells– they are made up of two electrodes enclosed in a glass bulb (evacuated or containing inert gas at low temperature). The cathode is a curved metal plate while the anode is normally a single metal rod)
They are used mostly in controlling lifts (doors) and reproducing the sound track in a film. Photoconductive cells – some semi-conductors such as cadmium sulphide (cds) reduces their resistance when light is shone at them (photo resistors). Other devices such as photo-diodes and photo-transistors block current when the intensity of light increases.
Photo-conductive cells
Photo-conductive cells are also known as light dependent resistors (LDR) and are used in alarm circuits i.e. fire alarms, and also in cameras as exposure meters.
Photo-voltaic cell– this cell generates an e.m.f using light and consists of a copper disc oxidized on one surface and a very thin film of gold is deposited over the exposed surfaces (this thin film allows light). The current increases with light intensity.
