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    MATHEMATIC FORM 3 END TERM EXAMS PLUS ANSWERS

    Hillary KangwanaBy

    ULTIMATE ACHIEVERS ACADEMY

    Name: ………………………………………………………….. …Date: ……………Adm No: …………

    FORM THREE

    TIME: 2 HOURS 30 MINUTES

    MATHEMATICS

    INSTRUCTIONS TO CANDIDATES

    1. Write your name, class and Admission Number in the spaces provided above.
    2. The paper consists of two sections. Section I and Section II.
    3. Answer ALL the questions in Section I.
    4. Answer only five questions only in Section II.
    5. All answers and working must be written on the question paper in the spaces provided below each question.
    6. Marks may be given for correct working even if the answer is wrong.
    7. Negligence and slovenly work will be penalized
    8. Non programmable silent electronic calculator and KNEC Mathematical tables may be used except where stated otherwise.

    FOR EXAMINER’S USE ONLY

    Section I

    Question 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 TOTAL
    Marks                                  

    Section II

    Question 17 18 19 20 21 22 23 24 TOTAL
    Marks                  
     

    GRAND TOTAL

     

    SECTION I (50 Marks)

    Answer all the questions in this section.

    1. Evaluate                                                                       (3 marks)

     

    1. By correcting each number to one significant figure, approximate the value of

    (788 X 0.006).

    Hence calculate the percentage error arising from this approximation              (3 marks)

     

     

     

     

     

    1. Three bells ring at intervals of 9 minutes, 15 minutes and 21 minutes. The bells will next ring together at 11.00pm. Find the time the bells had last rang together. (3 marks)

     

     

     

    1. Solve for x in the equation below (4 marks)

     

     

     

     

     

    1. Without using mathematical tables or calculator evaluate (3 marks)

     

     

     

     

     

     

     

    1. Simplify (3 marks)

     

     

    1. The figure below shoes two intersecting chords

    Find the length of UT                                                                                    (4 marks)

     

     

     

     

     

    1. Make h the subject of the formula (3 marks)

     

     

     

     

    1. Determine the integral values of which satisfy the inequalities below.(3 marks)

     

     

    1. Kambo bought a suit for Sh. 1200 and marked it at a price such that after allowing his customer a 10% discount, he would make a profit of 20%. Calculate the marked price of the suit. (3 marks)

     

     

     

     

     

     

    1. Given that , without using mathematical table, express in fraction form the value of;
    • (1 mark)

     

     

    • (2 marks)

     

     

     

     

    1. Given that evaluate (3 marks)

     

     

     

    1. On a certain map an estate is represented by an area of 48cm2. If the actual area of the estate is 1200 hectares, find the scale of the map in the form 1:n (3 marks)

     

     

     

    1. In the figure below ABCD is a rhombus whose diagonals AC and BD meet at X. Given that AC = 27.6cm and BD = 16.2 cm, calculate the area of the rhombus. (3 marks)

     

     

     

    1. The image of point (6, 4) is (3, 4) under a translation. Find the translation vector. (3 marks)

     

     

     

     

     

    1. The initial cost of a ranch is sh. 5 000 000. At the end of three years the value of the ranch increases to 5 306 040. Calculate to one significant figure the value at which the ranch appreciates. (3 marks)

     

     

    SECTION II (50 MARKS)

    Answer any FIVE Questions ONLY from this section

    1. Two shopkeepers Juma and Wanjiku bought some items from a wholesaler. Juma bought 18 loaves of bread, 40 packets of milk and 5 bars of soap while Wanjiku bought 15 loaves of bread, 30 packets of milk and 6 bars of soap. He prices of a loaf of bread, a packet of milk and a bar of soap were Ksh 45, Ksh 50 and Ksh 150 respectively.
    • Represent:
    • The number of items bought by Juma and Wanjiku using a matrix  (1 mark)

     

     

     

    • The prices of items bought using matrix                                          (2 marks)

     

     

     

    • Use the matrices in (a) above to determine the total expenditure incurred by each person and hence the difference in their expenditure.           (3 marks)

     

     

     

     

     

     

    • Juma and Wanjiku also bought rice and sugar. Juma bought 36kg of rice and 23kg of sugar and paid Kshs 8160. Wanjiku bought 50kg 0f rice and 32 kg of sugar and paid Kshs 11340. Use the matrix method to determine the price of one kilogram of rice and one kilogram of sugar.                                         (5 marks)

     

     

     

     

    1. The diagram below represents a steel girder used in construction work. The cross – section consists of a rectangle measuring 20cm by 14cm from which two similar semi – circles have been removed. The girder is 5m long and is made of steel whose density is 8.5g/cm3.
    • Calculate:
    • The cross – sectional area of the girder. (3 marks

     

     

     

     

     

    • The mass of the girder in kilograms. (4 marks)

     

     

     

     

     

     

    • The removed semi – circular troughs are filled with concrete whose density is 5.5g/cm3. Calculate the mass of concrete used to fill the removed parts of the girder. (3 marks)

    (Take π = )

     

     

     

     

    1. A country bus left town A at 11.45am and travelled towards town Bat an average speed of 60km/hr. A matatu left town B at 1.15pm on the same day and travelled along the same road at an average speed of 90km/hr. The distance between the two towns is 540km.

    Determine:

    • The time of the dsy when the two vehicles met.           (4 marks)

     

     

     

     

    • How far from town A they met. (2 marks

     

     

     

     

     

    • How far outside town B the bus was when the matatu reached town A, (4 marks)

     

     

     

     

     

     

     

     

     

    1. Two lines L1 whose equation is and L2 whose equation is intersect at point A.
    • Find the coordinates of point A. (3 marks)

     

     

     

     

     

     

    • A third line L3 is perpendicular to L2 at point A. find the equation of L3 in the form , where area constants.(3 marks)

     

     

     

     

     

     

     

     

    • Another line L4 is parallel to L1 and passes through. Find x and y intercepts of line L4. (4 marks)

     

     

     

     

     

     

     

     

     

    1. In June of a certainyear, an employee’s basic salary was Ksh 17 000. The employee was also paid a house allowance of Ksh 6 000, a commuter allowance of Ksh 2 500 and a medical allowance of Ksh 1 800. In July that year, the employee’s basic salary was raised by 2%.
    • Calculate the employee’s:
    • Basic salary in July.                    (2 marks)

     

     

     

    • Total taxable in the July of that year (2 marks)

     

     

     

    • In that year, the taxable income tax rates were as shown in the table below.
    Monthly taxable income (Kshs) Percentage rate of tax per shilling
    Up to 9680

    From 9681 to 18 800

    From 18 801 to 27 920

    From 27 921 to 37 040

    From 37 041 and above

    		 10%

    15%

    20%

    25%

    30%

    Given that the monthly personal relief was Ksh 1056, calculate the net tax paid by the employee.                                                                             (6 marks)

     

     

     

     

     

     

     

     

    1. In the triangle XYZ below line XY = 3cm, YZ = 4cm and XZ = 3.5 cm.

    Calculate:

    • Angle ZXY (4 marks)

     

     

     

     

     

    • Angle XYZ (2 marks)

     

     

     

     

     

    • Angle XZY (1 mark)

     

     

     

    • Calculate the area of the triangle XYZ to four significant figures. (3 marks)

     

     

    1. The 2nd and the 5th terms of an arithmetic progression are 8 and 17 respectively. The 2nd, the 10th and the 42nd terms of the arithmetic progression form the first three terms of a geometric progression. Find:
    • The first term and the common difference of the arithmetic progression. (3 marks)

     

     

     

     

     

     

     

     

     

    • The first three terms of the geometric progression and the 5th term of the geometric progression. (4 marks)

     

     

     

     

     

     

     

     

     

     

    • The sum of the first 4 terms of the geometric progression. (3 marks)

     

     

     

     

    1. By taking integral values of x, from x = – 2, to x=6 make a table of values for the function                                                                                                 (2marks)

     

     

     

    • On the same axes and using the scale of 1cm to 1 unit on the x-axis and 1cm to 5 units on the y–axis draw graphs of and (4marks)

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

    • From your graph;
    • Find the roots of the equations (1mark)

     

     

     

     

    • Write down the maximum value of (1mark)

     

     

     

     

     

    • Deduce the roots of the equation (2marks)

     

    MATHEMATICS Form 3

    MARKING SCHEME

    SECTION I

    NO WORKING MARKS GUIDELINES
    1.      

    M1

     

    M1

     

     

    A1

    		  
        03  
    2.       M1

     

    M1

     

    A1

    		  
        03  
    3.    
    3 21 15 9
    3 7 5 3
    5 7 5 1
    7 7 1 1
      1 1 1

     

    		  

    M1

     

     

    M1

     

    A1

    		  
        04  
    4.      thus

    thus

    		 M1

     

     

     

     

     

     

     

     

    M1

     

     

    A1

    		  
        03  
    5.      

    M1

     

    M1

     

    A1

    		  
        03  
    6.   M1

     

     

     

     

     

     

    M1

     

     

    A1

    		  
        3  
    7.     Ignoring negative answer  

    M1

     

     

    M1

     

     

     

     

     

     

     

    A1

    		  
        03  
    8.      

    M1

     

     

    M1

     

     

    A1

    		  
        03  
    9.      

     

    Integral values

    		  

     

    M1

     

     

     

     

    M1

     

    A1

    		  
        03  
    10.         M1

     

    M1

     

    A1

    		  
        03  
    11.         (a)

    (b)

    		  

     

     

     

     

     

    M1

     

    A1

     

    A1

    		  
        03  
    12.         Numerator:

    Denominator

    		 M1

     

     

    M1

     

    A1

    		  
        03  
    13.         M1

     

    M1

    A1

    		  
        03  
    14.         M1M1

     

    A1

    		  
        03  
    15.         M1

    M1

     

    A1

    		  
        03  
    16.          

    M1

     

     

     

     

     

    M1

     

     

    A1

    		  
        03  

    SECTION II

    NO WORKING MARKS GUIDELINES
    17.         (a)  (i)

     

    (ii)

     

     

    (b)

     

    Juma = sh 3560

    Wanjiku = sh 3075

     

    Difference = 3560 – 3075 = 485

     

     

    (c)

     

     

     

     

     

     

     

    		 B1

     

     

    B1

     

     

     

    M1

     

     

    M1

     

    A1

     

     

    M1

     

     

    M1

     

    M1

     

     

     

     

    M1

     

     

     

     

     

    A1

     

    		  

     

     

     

     

     

     

     

     

     

    For both answers
        10  
    18.         (a)  (i)

     

     

     

    (ii)

     

     

     

    (b) 

     

     

    		 M1

     

    M1

     

     

    A1

     

     

    M1

    M1

     

    M1

    A1

     

     

    M1

     

     

    M1

     

    A1

    		  
        10  
    19.       (a)  Time before the matatu started

    = 13.15 – 11.45 =

    Distance covered by the bus =

    Distance between them =

    Relative speed =

    Time taken to meet =

    Time they met = 1.15pm + 3 hours = 4.15pm

     

    (b)  Distance from town A to the point of meeting

    Time =

    Distance from A =

     

    (c)  Time taken by the matatu from B to A

    The matatu reaches A = 13.15pm +6hrs = 1915hrs

    Time travelled by the bus when the matatu reaches A

    1915hrs – 1145hrs =

    Distance moved by bus from A =

    Distance outside town B

    		  

     

    M1

     

    M1

     

    M1

    A1

     

     

     

    M1

    A1

     

    M1

     

     

    M1

     

    M1

    A1

    		  
        10  
    20.         (a) 

     

    Solving simultaneously

     

     

    (b)

    , (x ,y)

     

    (c) 

     

     

    		 M1

     

     

     

    M1

     

     

    A1

     

     

     

     

    M1

     

    M1

     

    A1

     

     

     

    M1

     

     

     

    M1

     

    A1

     

    A1

    		  
        10  
    21.         (a)  (i)

     

    (ii)

     

    (b) 

     

    Total tax      =  4104

     

    Net tax =

    = 3048

    		 M1

    A1

     

    M1

    A1

     

     

    M1

     

    M1

     

    M1

     

    M1

     

    M1

    A1

    		  
        10  
    22.         (a)

     

    (b)

     

    (c)

     

    (d)

    		M1

     

    M1

     

    M1

    A1

     

     

    M1

     

     

     

     

     

    A1

     

     

    A1

     

     

    M1

    M1

    A1

    		  
        10  
    23.         (a)      

     

     

    (b)      

    Geometric progression

     

     

     

    (c)      

     

     

     

    		 M1

     

     

     

    M1

     

     

     

    A1

     

     

     

     

     

     

    B1

    B1

    B1

     

    B1

     

     

     

     

     

     

    M1

     

    M1

     

     

    A1

    		  
        10  
    24.          

    x -2 -1 0 1 2 3 4 5 6
    12x -24 -12 0 12 24 36 48 60 72
    -3x2 -12 -3 0 -3 -12 -27 -48 -75 -108
    y -36 -15 0 9 12 9 0 -15 -36

                                                                            2 mks for correct table

    y = 5 ( x – 2 )

    y = 5 x – 10

    x 0 2 5
    y -10 0 15

     

    i) roots of 3 x ( 4 – x) = ) are x = 0, x = 4

     

    ii) Maximum value of y = 3x ( 4 – x )         when x = 2 , y = 12

    the maximum value of y = 12

     

    iii)   roots of equation 3x ( 4 – x ) = 5 ( x – 2 )  is where the curve cuts the line

    y    = 5 (x -2 )

    The roots arc x = -1  and x = 3.3 ± 0.1

     

    		 B1

    B1

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

    S1

    P1

    C1

    L1

     

     

     

     

     

     

     

     

     

     

    B1

     

    B1

     

     

     

    B1B1

    		 Table

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

    üB1 for both values of x
        10  

     

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