{"id":28234,"date":"2024-12-13T06:25:57","date_gmt":"2024-12-13T03:25:57","guid":{"rendered":"https:\/\/newsblaze.co.ke\/?p=28234"},"modified":"2024-07-03T21:49:18","modified_gmt":"2024-07-03T18:49:18","slug":"physics-main-electricity-revision-questions","status":"publish","type":"post","link":"https:\/\/newsblaze.co.ke\/physics-main-electricity-revision-questions\/","title":{"rendered":"PHYSICS MAIN ELECTRICITY REVISION QUESTIONS"},"content":{"rendered":"
MAIN ELECTRICITY<\/u><\/strong><\/p>\n\n- What current will a 500W resistor connected to a source of 240V draw?<\/li>\n
- Name a device used to change light energy directly into electrical energy.<\/li>\n
- When a current of 2.0A flows in a resistor for 10 minutes, 15000 Joules of electrical energy is dissipated. Determine the voltage across the resistor.<\/li>\n
- An electric bulb rated 40W is operating on 240v mains. Determine the resistance of its filament.<\/li>\n
- An electric heater rated 240V, 3000V is to be connected to a 240V mains supply, through a 10A fuse. Determine whether the fuse is suitable or not.<\/li>\n
- A 60W bulb is used continuously for 36 hours. Determine the energy consumed, giving your answer in kilowatt hour (Kwh)<\/li>\n
- How many 100W electric irons could be safely be connected to a 240V mains circuit fitted with a 13A fuse?<\/li>\n
- Find the maximum number of 75W bulbs that can be connected to a 13A fuse on a mains supply of 240V.<\/li>\n
- Determine the cost of using an electrical iron box rated 1500W, for a total of 30 hours given that the cost of electricity per Kwh is Kshs. 8.<\/li>\n
- State Ohm\u2019s law.<\/li>\n
- Electrical energy costs Kshs. 1 per Kwh unit. Find the cost of using an electric heater of power 1.5 KW for a day.<\/li>\n
- The figure below represents part of the main circuit.<\/li>\n<\/ol>\n
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\n- i) Explain why it is not advisable to fix a fuse on neutral line.<\/li>\n
- ii) Explain why there are fuses of different rating in the distribution box.<\/li>\n
- Calculate the power of a devise which has a p.d of 250V applied across it when a current of 0.5A passes through it.<\/li>\n
- An electric iron box is rated 2500W and uses a voltage of 240V. Given that electricity costs Kshs. 1.10 per Kwh, what is the cost of using it for 6 hours?<\/li>\n
- Four 40 w bulbs and seven 100W are switched on for 3 hours a day for domestic monthly bill given the cost of electricity is sh. 3.50 per unit (Take 1 month = 30 days)<\/li>\n
- a) Give one advantage of transmitting mains electricity as a.c and not d.c.<\/li>\n
- \nb) The figure below shows part of a wiring circuit for a house.<\/li>\n<\/ol>\n
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Identify two faults in the wiring.<\/p>\n
\n- c) The figure shows a connection to the pin plug.<\/li>\n<\/ol>\n
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\n- i) State the colour of the leads labelled A, B and C.<\/li>\n<\/ol>\n
A \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026<\/p>\n
B \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026<\/p>\n
C \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026<\/p>\n
\n- ii) Why is the earth pin normally longer than the two pins?<\/li>\n<\/ol>\n
iii) What is the function of the fuse?<\/p>\n
\n- d) The power company supplied electrical energy and charges the consumption to ordinary domestic wiring as follows;<\/li>\n<\/ol>\n
– A monthly fixed charge of Ksh. 75<\/p>\n
– Ksh. 1.55 per unit for the first 50 units consumed.<\/p>\n
– Ksh. 6.65 per unit for the next 51- 300 units<\/p>\n
1 unit = 1kilowatt- hour (kwh)<\/p>\n
A consumer uses 1.98 x 105<\/sup> kilojoules of electrical energy in a given month. Determine the total month bill.<\/p>\n\n- The figure below shows a connection to the three pin plug.<\/li>\n
- i) Identify the mistakes in this wiring.<\/li>\n
- ii) State two reasons why the earth pin is normally longer than the other two pins.<\/li>\n
- (a) Figure 10<\/strong> shows a section of a house wiring syste<\/li>\n<\/ol>\n
(i). \u00a0\u00a0\u00a0\u00a0\u00a0 Name:<\/p>\n
The circuit labelled P<\/p>\n
The terminals labelled X and Y<\/p>\n
X\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026<\/p>\n
Y\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026<\/p>\n
(ii) \u00a0\u00a0\u00a0\u00a0 State the purpose of R in the circuit<\/p>\n
(iii) \u00a0\u00a0\u00a0 Give the reason why R is connected to Y but not to X<\/p>\n
(iv) \u00a0\u00a0\u00a0 Why is the earthing necessary in such a circuit?<\/p>\n
(b) \u00a0\u00a0\u00a0\u00a0 Determine the cost of using an electric iron rated 1500W, for a total of 30 hours given that the cost of electricity per kWh is Ksh. 8<\/p>\n
\n- (a)A transformer has 800 turns in the primary windings. The alternating e.m.f connected to the primary is 240V and the current flowing is 0.2A. Find the power in the secondary coil if the transformer is 90% efficient<\/li>\n<\/ol>\n
(b) The figure below shows a domestic wiring system.<\/p>\n
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(i) Point out two faults in the circuit.<\/p>\n
(ii)\u00a0\u00a0\u00a0\u00a0 What is the fuse made of and why is it necessary in the circuit?<\/p>\n
(c) State 2 ways of minimizing power loss in transmission lines.<\/p>\n
\n- A transformer has 800 turn in the primary and 40 turns in the secondary winding. The alternating e.m.f connected to the primary is 240v and the current is 0.5A.<\/li>\n<\/ol>\n
Determine<\/p>\n
\n- The secondary e.m.f<\/li>\n
- The power in the secondary if the transformer is 95% efficient.<\/li>\n
- c) Explain how energy losses in a transformer are reduced by having<\/li>\n
- A soft-iron core<\/li>\n
- A laminated core. (<\/li>\n
- A transformer with 2000 turns in the primary circuit and 150 turns in the secondary circuit has its primary circuit connected to a 800V a.c source. It is found that when a heater is connected to the secondary circuit, it produced heat at the rate of 1000W. Assuming 100% efficiency, determine the;<\/li>\n
- Voltage in the secondary circuit.<\/li>\n
- Current in the primary circuit.<\/li>\n<\/ol>\n
\n- Current in the secondary circuit.<\/li>\n<\/ul>\n
\n- State the type of transformer represented above.<\/li>\n
- State the reason why long distance power transmission is done at a very high voltage and using thick cables.<\/li>\n
- Calculate the cost of using the following appliances in one month (30 days ) if the company rate is ksh. 9.50 per unit.<\/li>\n<\/ol>\n
I\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 A 2000W water heater for 2 hours per day.<\/p>\n
II\u00a0\u00a0\u00a0\u00a0\u00a0 A 75W bulb for 10 hour per day.<\/p>\n
III\u00a0\u00a0\u00a0\u00a0 A 1500W electric iron for 1 hour per day.<\/p>\n
\n- Figure 6 below shows a part of housing wiring system<\/li>\n<\/ol>\n
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\n- Name (i) The\u00a0 circuit labeled p<\/li>\n
- The terminal labeled X and Y<\/li>\n<\/ol>\n
\n- State the purpose of R in the circuit<\/li>\n<\/ul>\n
\n- Give a reason why R is connected to Y but not to x<\/li>\n
- Why is earthing necessary in such a circuit.<\/li>\n<\/ol>\n
Determine the cost of using an electric iron rated at 1.5Kw for a total of 40 hours if he cost of\u00a0 electricity is Ksh 8 per unit.<\/p>\n
\n- (a) Long distance transmission of power is done at a very high voltage.<\/li>\n<\/ol>\n
\n- Figure 10 below shows a section of a house wiring system.<\/li>\n<\/ul>\n
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\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n <\/p>\n
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\n- Name:<\/li>\n<\/ul>\n
I \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The circuit labelled F<\/strong>.<\/p>\nII\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The terminals A<\/strong> and B<\/strong>.<\/p>\n\n- Give a reason why R<\/strong> is connected to B<\/strong> and not A<\/strong>.<\/li>\n
- What is R<\/strong>?<\/li>\n
- Why is earthing necessary in such a circuit?<\/li>\n<\/ul>\n
\n- 54kg of water in a metallic cylinder of heat capacity 9000JK\u02c9\u00b9 is heated from 10\u00b0C to 80\u00b0C using an immersion heater rated 1800W, 240V. Assuming that no heat is lost to the surrounding and the immersion heater works at its correct voltage.<\/li>\n
- The current flowing through the water.<\/li>\n
- The cost of heating the same mass of water from 10\u00b0C to 80\u00b0C, every day for 30 days, if electricity cost sh.6.70 per unit.<\/li>\n<\/ul>\n
\n- (i) State the reason why long distance power transmission is done at a very high voltage and using thick cables.<\/li>\n<\/ol>\n
(ii)\u00a0 Calculate the cost of using the following appliances in one month (30 days) if the company rate is Ksh. 9.50 per unit.<\/p>\n
\n- A 2000W water heater for 2 hours per day.<\/li>\n
- A 75W bulb for 10 hours per day.<\/li>\n<\/ol>\n